Question #163639

The base of a mountain is at sea level where the gravitational field strength is 9.810N/kg. The value of the gravitational field strength at the top of the mountain is 9.790N/kg. Calculate the height of the mountain above the sea level.

1
Expert's answer
2021-02-22T10:27:34-0500

By the definition of the gravitational field strength, we have:


g=GMR2.g=\dfrac{GM}{R^2}.

Then, we can write:


gseagtop=GMR2GM(R+h)2=(R+h)2R2,\dfrac{g_{sea}}{g_{top}}=\dfrac{\dfrac{GM}{R^2}}{\dfrac{GM}{(R+h)^2}}=\dfrac{(R+h)^2}{R^2},gseagtop=R+hR,\sqrt{\dfrac{g_{sea}}{g_{top}}}=\dfrac{R+h}{R},h=R(gseagtop1),h=R(\sqrt{\dfrac{g_{sea}}{g_{top}}}-1),h=6.38106 m(9.81 Nkg9.79 Nkg1)=6513 m.h=6.38\cdot10^6\ m\cdot(\sqrt{\dfrac{9.81\ \dfrac{N}{kg}}{9.79\ \dfrac{N}{kg}}}-1)=6513\ m.

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