Question

What is maximum height in projectile motion.

Answer 1

The maximum height of the projectile is the height at which the vertical velocity of the projectile becomes zero. The maximum height of the projectile can be found as follows:

$$y_{max}=\dfrac{v_0^2sin^2\theta}{2g},$$

here, $v_0$ is the initial velocity of the projectile, $\theta$ is the launch angle and $g$ is the acceleration due to gravity.