(a) Let's first find the force that provides an engine of the car:
P=Fv,F=vP=6 sm14.28⋅103 W=2380 N.Then, we can find the acceleration of the car from the Newton's Second Law of Motion:
F−R1−R2=(m1+m2)a,a=m1+m2F−R1−R2,a=1400 kg+700 kg2380 N−630 N−280 N=0.7 s2m.(b) Applying the Newton's Second Law of Motion, we get:
F−R1−T=m1a,T=F−R1−m1a,T=2380 N−630 N−1400 kg⋅0.7 s2m=770 N.
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