(a) Let's first find the force that provides an engine of the car:
"P=Fv,""F=\\dfrac{P}{v}=\\dfrac{14.28\\cdot10^3\\ W}{6\\ \\dfrac{m}{s}}=2380\\ N."Then, we can find the acceleration of the car from the Newton's Second Law of Motion:
"F-R_1-R_2=(m_1+m_2)a,""a=\\dfrac{F-R_1-R_2}{m_1+m_2},""a=\\dfrac{2380\\ N-630\\ N-280\\ N}{1400\\ kg+700\\ kg}=0.7\\ \\dfrac{m}{s^2}."(b) Applying the Newton's Second Law of Motion, we get:
"F-R_1-T=m_1a,""T=F-R_1-m_1a,""T=2380\\ N-630\\ N-1400\\ kg\\cdot0.7\\ \\dfrac{m}{s^2}=770\\ N."
Comments
Leave a comment