Question #157165
A particle P of mass 2m lies on a rough horizontal table. P is connected by a light inextensible string passing over a smooth pulley fixed at the edge of the table to another particle Q of mass 5m, hanging freely. The system is released from rest with the string taught and the hanging part vertical. If the acceleration of the system is of magnitude 4g/7, find
(a) the tension in the string
(b) the coefficient of friction between the first particle and the table.
1
Expert's answer
2021-02-06T10:07:22-0500

Let's solve the problem.

we have a=4g7a = \large\frac{4g}{7}

first of all we mark the directions of x and y forces which impact to P and Q particles


 for P particle: N=2mg    2ma=TFff=TμN=Tμ2mgN = 2mg \space\space\space\space 2ma = T - F_{ff} = T - \mu N = T - \mu 2mg

for Q particle: 5ma=5mgT5ma = 5mg - T

{2ma=Tμ2mg5ma=5mgT\begin{cases} 2ma = T - \mu 2mg \\ 5ma = 5mg - T \end{cases}    +7ma=5mg2μmg/:m+ \to 7ma = 5mg-2\mu mg / : m

                                                                  7a=5g2μg7a = 5g - 2\mu g

                                                                μ=5g7a2g\mu = \large\frac{5g-7a}{2g} =2.53.5ag= 2.5-3.5\large\frac{a}{g} = 527247\large\frac{5}{2}-\frac{7}{2}*\frac{4}{7} =0.5= 0.5

(b) the coefficient of friction between the first particle and the table is 0.5

(a)  the tension in the string is T=5m(a+g)=5m(g+4g7)=55mg7T = 5m(a+g) = 5m(g + \large\frac{4g}{7}) = \frac{55mg}{7}


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