Let's solve the problem.
we have "a = \\large\\frac{4g}{7}"
first of all we mark the directions of x and y forces which impact to P and Q particles
for P particle: "N = 2mg \\space\\space\\space\\space 2ma = T - F_{ff} = T - \\mu N = T - \\mu 2mg"
for Q particle: "5ma = 5mg - T"
"\\begin{cases}\n 2ma = T - \\mu 2mg \\\\\n 5ma = 5mg - T\n\\end{cases}" "+ \\to 7ma = 5mg-2\\mu mg \/ : m"
"7a = 5g - 2\\mu g"
"\\mu = \\large\\frac{5g-7a}{2g}" "= 2.5-3.5\\large\\frac{a}{g}" = "\\large\\frac{5}{2}-\\frac{7}{2}*\\frac{4}{7}" "= 0.5"
(b) the coefficient of friction between the first particle and the table is 0.5
(a) the tension in the string is "T = 5m(a+g) = 5m(g + \\large\\frac{4g}{7}) = \\frac{55mg}{7}"
Comments
Leave a comment