Answer
Using energy conservation
work done = kinetic energy
Fd=mv22Fd=\frac{mv^2}{2}Fd=2mv2
Mass is given by
m=2Fdv2=2×0.12×5025m=\frac{2Fd}{v^2}=\frac{2\times0.12\times50}{25}m=v22Fd=252×0.12×50
m=0.48Kg
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