Answer to Question #147673 in Mechanics | Relativity for Alina

Question #147673
8 A plank AB has mass 10kg and length 6m. It is held in equilibrium in a horizontal position by two ropes attached at the points C and D, where AC= 1 m and DB = 2m. The plank can be modelled as a uniform rod and the ropes as light strings. a Work out: i the tension in the rope at C ii the tension in the rope at D. A mass of 5kg is placed on the plank at a distance xm from C, between Cand D. The mass can be modelled as a particle. Given that the plank remains in equilibrium in the horizontal position, b find, in terms of x, an expression for the tension in the rope at D. The rope at D will break if the tension exceeds 10g N. The rope at C cannot break. e Work out the range of possible values of x.
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Expert's answer
2020-12-02T07:34:21-0500

a) We have can calculate tensions at C and D pionts:

Tc×\times 3m=M×\timesg×\times1m, Tc=M×g3\frac{M\times g}{3}=33.33N

2m×\timesM×\timesg=3m×\timesTD--->TD=2×\timesM×g3\frac{M\times g}{3}=66.66N

b) We can find expression:

x×\times5×\timesg+2×\times6×\timesg=3×\timesT -->T=50×x+1203\frac{50\times x+120}{3} this is answer.


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