Question

If the magnitude of the resultant force is to be 9kN directed along the positive x axis, determine the magnitude of force T acting on the eyebolt and its angle delta.

Answer 1

$T=\sqrt{8^2+9^2-2(8)(9)\cos45}$

$T=6.57KN$

$\theta= \frac {\sin 45}{6.57}$

$\theta= 30.6\degree$