Question #134074
A mass of m is sliding on a inclined plane of mass M which is kept on smooth surface find displacement of mass M.
1
Expert's answer
2020-09-23T11:46:29-0400

let the angle of inclination be θ\theta


As clearly seen from the figure,

then the net force acting on mass m in downward direction is

f= mgsinθfsmgsin\theta-f_s

Where fsf_s is frictional force on inclined surface

According to Newton's Law Third law,

This force also equal to the force on the inclined plane in upward direction as shown in figure


f=mgsinθusmgcosθmgsin\theta-u_smgcos\theta

Let the horizontal force on Mass M be F

then f=F cosθ\theta

Fcosθ=mg(sinθuscosθ)Fcos\theta=mg(sin\theta-u_scos\theta)


F=mg(tanθus)F=mg(tan\theta-u_s) ....(1)


Let the acelaration of complete system be a

( m +M ) a=F

a=F(m+M)\frac{F}{(m+M)}


Displacement in time t is given by second equation of motion as

s=ut+12at2ut+\frac{1}{2}at^2

u=0(initial velocity is 0)

=12×Fm+M×t2\frac{1}{2}\times\frac{F}{m+M}\times t^2

=mg(tanθus)t22(m+M)\frac{mg(tan\theta-u_s)t^2}{2(m+M)}





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