Let plank is large enough. Since external force acting on the plank is zero hence center of mass of the system will remain same.
If d is distance travelled by man and x is distance travelled by plank then in center of mass frame,
30d=(30+100)(x)30 d = (30 + 100)(x)30d=(30+100)(x)
x=30130d=313dx = \frac{30}{130} d = \frac{3}{13}dx=13030d=133d
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