solution:-
consider a rigid body of mass (M) hinged at point R as shown in figure.there is no friction between hinge and body.
if body is displaced from equilibrium by an angle "\\theta" . then restoring torque can be written as
"\\tau=-Mgl\\sin\\theta" .....eq.1
where "l" is the distance from hinged point R to center of gravity.
for small oscillation
"\\sin\\theta\u2248\\theta"
and torque for a rigid body can be given
"\\tau=I\\alpha" ............eq.2
where "I" is moment of inertia of body about hinged point and "\\alpha" is angular acceleration of body.
by the equation 1 and 2 we can written as
"-Mgl\\theta=I\\alpha"
"\\frac{\\theta}{\\alpha}=-\\frac{I}{Mgl}"
there are "-\\theta" is proportional to "\\alpha" so its simple harmonic motion. and time period can be given as
"T=2\\pi\\sqrt\\vert\\frac{\\theta}{\\alpha}\\vert"
"\\fcolorbox{green}{yellow}{$T=2\\pi\\sqrt\\frac{I}{Mgl}$}"
this is the time period of oscillation for rigid hinged body.
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