"let's\\ assume\\ that \\;the\\ length\\ of \\;the\\ pole\\\\ resting \\;relative\\; to\\\\ the \\;shed\\; is\\; equal \\;to\\ L=16\\ unit\\\\ then\\ according\\ to\\; the \\;Lorentz\\ transformations\\\\(by\\ the\\ terms) \\;the\\ length\\ of\\ a\\ pole\\\\ moving\\ relative \\;to\\ a\\ shed\\\\ at\\ the\\ speed\\ of\\ v\\ is\\ equal\\ to\\;\\frac{L}{2}=8\\;unit .\\;So\\\\\\frac{L}{2}=L\\sqrt{1-\\frac{v^2}{c^2}}; \\sqrt{1-\\frac{v^2}{c^2}}=\\frac{1}{2};\\\\1-\\frac{v^2}{c^2}=\\frac{1}{4}; v=\\frac{c}{2}\\sqrt{3}; v=\\frac{3\\times10^8}{2}\\times1.73;\\\\v=2.6\\times10^8\\frac{m}{c}.\\\\Answer: v=2.6\\times10^8\\frac{m}{c}\\;or\\; v=0.87c"
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