Question #131135

Suppose a pole vaulter, holding a 16 unit long pole parallel to his direction of motion, runs through an 8 unit long shed which is open at each end. At what speed should a pole vaulter be running such that the pole is entirely in the shed before it strikes the exit door?

Expert's answer

lets assume that  the length of  the poleresting  relative  tothe  shed  is  equal  to L=16 unitthen according to  the  Lorentz transformations(by the terms)  the length of a polemoving relative  to a shedat the speed of v is equal to  L2=8  unit.  SoL2=L1v2c2;1v2c2=12;1v2c2=14;v=c23;v=3×1082×1.73;v=2.6×108mc.Answer:v=2.6×108mc  or  v=0.87clet's\ assume\ that \;the\ length\ of \;the\ pole\\ resting \;relative\; to\\ the \;shed\; is\; equal \;to\ L=16\ unit\\ then\ according\ to\; the \;Lorentz\ transformations\\(by\ the\ terms) \;the\ length\ of\ a\ pole\\ moving\ relative \;to\ a\ shed\\ at\ the\ speed\ of\ v\ is\ equal\ to\;\frac{L}{2}=8\;unit .\;So\\\frac{L}{2}=L\sqrt{1-\frac{v^2}{c^2}}; \sqrt{1-\frac{v^2}{c^2}}=\frac{1}{2};\\1-\frac{v^2}{c^2}=\frac{1}{4}; v=\frac{c}{2}\sqrt{3}; v=\frac{3\times10^8}{2}\times1.73;\\v=2.6\times10^8\frac{m}{c}.\\Answer: v=2.6\times10^8\frac{m}{c}\;or\; v=0.87c


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