solution:-
in order for earth to became a blackhole without losing any mass its escape velocity should be at least equal to speed of light.
2 G M e R = c \sqrt{\frac{2GM_e}{R}}=c R 2 G M e = c
where G=gravitation constant( 6.67 × 1 0 − 11 N m 2 / k g 2 ) (6.67\times10^{-11}Nm^2/kg^2) ( 6.67 × 1 0 − 11 N m 2 / k g 2 )
mass of earth M e = 5.9 × 1 0 24 k g M_e=5.9\times10^{24}kg M e = 5.9 × 1 0 24 k g
speed of light( c ) = 3 × 1 0 8 m / s (c)=3\times10^8m/s ( c ) = 3 × 1 0 8 m / s
then radius of earth should be after compressed
R = 2 G M e c 2 R=\frac{2GM_e}{c^2} R = c 2 2 G M e
by putting the value of G,Me and c
R = 2 × 6.67 × 1 0 − 11 × 5.98 × 1 0 24 9 × 1 0 16 R=\frac{2\times6.67\times10^{-11}\times5.98\times10^{24}}{9\times10^{16}} R = 9 × 1 0 16 2 × 6.67 × 1 0 − 11 × 5.98 × 1 0 24
R = 0.886 × 1 0 − 2 m R=0.886\times10^{-2}m R = 0.886 × 1 0 − 2 m
R ≈ 1 0 − 2 m \fcolorbox{green}{yellow}{$R≈10^{-2}m$} R ≈ 1 0 − 2 m
therefore radius of earth should be 1 cm to became a blackhole.
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