solution:-
in order for earth to became a blackhole without losing any mass its escape velocity should be at least equal to speed of light.
2GMeR=c\sqrt{\frac{2GM_e}{R}}=cR2GMe=c
where G=gravitation constant(6.67×10−11Nm2/kg2)(6.67\times10^{-11}Nm^2/kg^2)(6.67×10−11Nm2/kg2)
mass of earth Me=5.9×1024kgM_e=5.9\times10^{24}kgMe=5.9×1024kg
speed of light(c)=3×108m/s(c)=3\times10^8m/s(c)=3×108m/s
then radius of earth should be after compressed
R=2GMec2R=\frac{2GM_e}{c^2}R=c22GMe
by putting the value of G,Me and c
R=2×6.67×10−11×5.98×10249×1016R=\frac{2\times6.67\times10^{-11}\times5.98\times10^{24}}{9\times10^{16}}R=9×10162×6.67×10−11×5.98×1024
R=0.886×10−2mR=0.886\times10^{-2}mR=0.886×10−2m
R≈10−2m\fcolorbox{green}{yellow}{$R≈10^{-2}m$}R≈10−2m
therefore radius of earth should be 1 cm to became a blackhole.
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