first the work done by friction to stop the car needs to be obtained , and from it calculate the speed
The change in the cars kinetic energy is equal to the work done by the frictional force to stop the car.
Therefore
"\\Delta k= -f_k"
"-(\\frac{1}{2}mv_i^{2}-\\frac{1}{2}mv_f^{2})= -\\mu mgd"
now making the initial velocity subject of the formula
"v_i= \\sqrt {2(\\mu gd+\\frac{1}{2}}v_f^{2})"
substituting the given values "\\mu= 0.45" , "g=9.8m\/s^{2}" ,"d=250 ft\\space or\\space 76.2m","v_f^{2}=0m\/s" in the equation
"v_i=\\sqrt{2(0.45\\times9.8\\times76.2)+0}"
"v_i=25.9m\/s\\space or\\space 57.98mph"
This is the speed Nick was travelling at before he hit the brakes, therefore he should fight the ticket in court since he had not exceeded the 60 mph limit
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