Question

In an electric shaver, the blade moves back and forth over a distance of 2.0mm in simple harmonic
motion, with a frequency 120Hz. Find (a) the amplitude, (b) the maximum blade speed and (c) the
magnitude of the maximum acceleration of blade.

Answer 1

(a) $A=L/2=2/2=1mm$

(b) $v=\omega A=2\pi fA=2\cdot3.14\cdot120\cdot0.001=0.75m/s$

(c) $a=\omega^2A=(2\pi f)^2A=(2\cdot3.14\cdot 120)^2\cdot 0.001=568m/s^2$