The law of the motion with the constant acceletation (from the origin of the coordinates and from rest):
xbus(t)=2at2 where x(t) is the bus coordinate at time t.
The law of the car's motion (constant speed, starts from the origin):
xcar(t)=vt The time at which the bus will overtake the car satisfies the following consition:
xbus(tovertake)=xcar(tovertake)2atovertake2=vtovertake⇒tovertake=a2v=52⋅50=20s The distans of the meeting then:
d=xcar(tovertake)=vtovertake=50⋅20=1000m The speed of the bus at that time will be:
vbus=atovertake=5⋅20=100m/s
Answer. d = 1000 m, v = 100 m/s.
Comments
Leave a comment