Question #112401

A jet of water of 10 mm diameter impinges normally on a smooth flat

plate of 50 N in weight as depicted below. The water is deflected and

flows out along the plate and the plate remains stationary. Assume the

friction loss and head difference are negligible, determine the flow rate.

Expert's answer

Let the flow rate be vmsecv \frac{m}{sec}

Now

Rate of change of momentum = weight = 50 N


Sodmdt×v=50So\\\frac{dm}{dt}\times v= 50

(ρ×π r2×v)×v=501000×3.14×(5×103)2×v2=50v2=636.94v=25.24 msec(\rho\times\pi \ r^2\times v) \times v= 50\\1000\times 3.14\times(5\times10^{-3})^2\times v^2=50\\v^2= 636.94\\v=25.24\ \frac{m}{sec}


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