Question

7. A particle is projected horizontally at 15ms-1 from height of 20m. Calculate the horizontal distance covered
by the particle just before hitting the ground (g = 10ms-2).

Answer 1

Given:

${v_0=15\:\rm m/s},\\ {H=20\:\rm m/s},\\ {g=10\:\rm m/s^2}.$

The horizontal distance

$$H=v_0\sqrt{\frac{2H}{g}}=15\sqrt{\frac{2\times 20}{10}}=30\:\rm m.$$