Since it used a same power, then
P1=P2=mght1=mght2→t1=t2=t=30sP_1=P_2=\frac{mgh}{t_1}=\frac{mgh}{t_2}\to t_1=t_2=t=30 sP1=P2=t1mgh=t2mgh→t1=t2=t=30s
In the second case, the monkey passed 75m75 m75m.
So,
v=75/30=2.5m/sv=75/30=2.5m/sv=75/30=2.5m/s.
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