Question #102926

Kinematics

A dust particle kicked by Neil Armstrong on the moon leaves the lunar surface travelling at 2.0 m/s upwards. It moves upwards to a maximum height and then begins to falling back downwards. When it return to neils waist height on its descent( a height of 120cm above the lunar surface) it is falling at 33 cm/s


Determine the acceleration

Maximum height

And how long it takes from being kicked upwards to reach neils waist height on its descent

Expert's answer

From the coservation of energy:


0.5mv2=0.5mu2+mah0.5mv^2=0.5mu^2+mah

Acceleration:

a=v2−u22h=22−0.3322(1.2)=1.6ms2a=\frac{v^2-u^2}{2h}=\frac{2^2-0.33^2}{2(1.2)}=1.6\frac{m}{s^2}

Maximum height:


H=v22(a)=222(1.6)=1.25 mH=\frac{v^2}{2(a)}=\frac{2^2}{2(1.6)}=1.25\ m

t=t1+t2=va+ua=v+uat=t_1+t_2=\frac{v}{a}+\frac{u}{a}=\frac{v+u}{a}

t=2+0.331.6=1.46 st=\frac{2+0.33}{1.6}=1.46\ s


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