2020-02-12T10:42:03-05:00
A hicker begins a trip by first walking 25 km south east from her car then she walks 40 km in a direction 60 degree centigrade north of East (a) determine the component for each displacement (b) determine R esultant displacement
1
2020-02-13T08:53:48-0500
a)
d 1 x = 25 cos 45 = 17.68 k m d_{1x}=25\cos{45}=17.68\ km d 1 x = 25 cos 45 = 17.68 km
d 1 y = − 25 sin 45 = − 17.68 k m d_{1y}=-25\sin{45}=-17.68\ km d 1 y = − 25 sin 45 = − 17.68 km
d 2 x = 40 cos 60 = 20 k m d_{2x}=40\cos{60}=20\ km d 2 x = 40 cos 60 = 20 km
d 2 y = 40 sin 60 = 34.64 k m d_{2y}=40\sin{60}=34.64\ km d 2 y = 40 sin 60 = 34.64 km b)
R x = 17.68 + 20 = 37.68 k m R_x=17.68+20=37.68\ km R x = 17.68 + 20 = 37.68 km
R y = − 17.68 + 34.64 = 16.96 k m R_y=-17.68+34.64=16.96\ km R y = − 17.68 + 34.64 = 16.96 km The magnitude:
R = 37.6 8 2 + 16.9 6 2 = 41.3 k m R=\sqrt{37.68^2+16.96^2}=41.3\ km R = 37.6 8 2 + 16.9 6 2 = 41.3 km The direction:
θ = arctan 16.96 37.68 = 24.2 ° N o f E \theta=\arctan{\frac{16.96}{37.68}}=24.2\degree N\ of\ E θ = arctan 37.68 16.96 = 24.2° N o f E
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