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Question #102865
An aeroplane flies from origin to city located 175 kilometre 30 degree northof East next it flies 153 kilometre 20 degree centigrade west of north to city B.finally it flies 195 kilometre due West to city C find the total displacement
Expert's answer
s
1
=
(
−
175
cos
30
,
175
sin
30
)
=
(
−
151.6
,
87.5
)
k
m
\bold{s_1}=(-175\cos{30},175\sin{30})=(-151.6,87.5)km
s
1
=
(
−
175
cos
30
,
175
sin
30
)
=
(
−
151.6
,
87.5
)
km
s
2
=
(
153
sin
20
,
153
cos
20
)
=
(
52.3
,
143.8
)
k
m
\bold{s_2}=(153\sin{20},153\cos{20})=(52.3,143.8)km
s
2
=
(
153
sin
20
,
153
cos
20
)
=
(
52.3
,
143.8
)
km
s
3
=
(
195
,
0
)
k
m
\bold{s_3}=(195,0)km
s
3
=
(
195
,
0
)
km
s
x
=
195
+
52.3
−
151.6
=
95.7
k
m
s_x=195+52.3-151.6=95.7\ km
s
x
=
195
+
52.3
−
151.6
=
95.7
km
s
y
=
87.5
+
143.8
=
231.3
k
m
s_y=87.5+143.8=231.3\ km
s
y
=
87.5
+
143.8
=
231.3
km
The magnitude:
s
=
95.
7
2
+
231.
3
2
=
250
k
m
s=\sqrt{95.7^2+231.3^2}=250\ km
s
=
95.
7
2
+
231.
3
2
=
250
km
The direction:
θ
=
arctan
95.7
231.3
=
22.5
°
W
o
f
N
\theta=\arctan{\frac{95.7}{231.3}}=22.5\degree W\ of\ N
θ
=
arctan
231.3
95.7
=
22.5°
W
o
f
N
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