Question #102289

A home run is hit in such a way that the baseball just clears a wall 20.0 m high, located 136 m from home plate. The ball is hit at an angle of 37.0° to the horizontal, and air resistance is negligible. (Assume that the ball is hit at a height of 1.0 m above the ground.)

Expert's answer

We need to find the initial speed of the ball.

The time to reach the fence is


t=xvcos⁡37=136vcos⁡37t=\frac{x}{v\cos{37}}=\frac{136}{v\cos{37}}

y=y0+vsin⁡37t−0.5gt2y=y_0+v\sin{37}t-0.5gt^2

20=1+vsin⁡37(136vcos⁡37)−0.5(9.8)(136vcos⁡37)220=1+v\sin{37}\left(\frac{136}{v\cos{37}}\right)-0.5(9.8)\left(\frac{136}{v\cos{37}}\right)^2

v=41.3msv=41.3\frac{m}{s}


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