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Question #102289
A home run is hit in such a way that the baseball just clears a wall 20.0 m high, located 136 m from home plate. The ball is hit at an angle of 37.0° to the horizontal, and air resistance is negligible. (Assume that the ball is hit at a height of 1.0 m above the ground.)
Expert's answer
We need to find the initial speed of the ball.
The time to reach the fence is
t
=
x
v
cos
37
=
136
v
cos
37
t=\frac{x}{v\cos{37}}=\frac{136}{v\cos{37}}
t
=
v
cos
37
x
=
v
cos
37
136
y
=
y
0
+
v
sin
37
t
−
0.5
g
t
2
y=y_0+v\sin{37}t-0.5gt^2
y
=
y
0
+
v
sin
37
t
−
0.5
g
t
2
20
=
1
+
v
sin
37
(
136
v
cos
37
)
−
0.5
(
9.8
)
(
136
v
cos
37
)
2
20=1+v\sin{37}\left(\frac{136}{v\cos{37}}\right)-0.5(9.8)\left(\frac{136}{v\cos{37}}\right)^2
20
=
1
+
v
sin
37
(
v
cos
37
136
)
−
0.5
(
9.8
)
(
v
cos
37
136
)
2
v
=
41.3
m
s
v=41.3\frac{m}{s}
v
=
41.3
s
m
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on Dec 2023
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