v0=8.0 m/sv_0=8.0\; m/sv0=8.0m/s
a=−9.8 m/s2a=-9.8\; m/s^2a=−9.8m/s2
t=4 st=4\;st=4s
v,Δy − ?v, \Delta y \;-\;?v,Δy−?
Solution:
v=v0+atv=v_0+atv=v0+at
v=8.0+(−9.8)×4=−31.2 m/sv=8.0+(-9.8)\times4=-31.2 \; m/sv=8.0+(−9.8)×4=−31.2m/s
Δy=v0t+12at2\Delta y=v_0t+\frac{1}2at^2Δy=v0t+21at2
Δy=8.0×4+12(−9.8)×42=−46.4 m\Delta y=8.0\times 4+\frac{1}{2}(-9.8)\times 4^2=-46.4 \;mΔy=8.0×4+21(−9.8)×42=−46.4m
Answers: v=−31.2 m/s, Δy=−46.4 m.v=-31.2\; m/s, \; \Delta y=-46.4\; m.v=−31.2m/s,Δy=−46.4m.
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