Answer to Question #102201 in Mechanics | Relativity for grr

Question #102201
Suppose Ichiro threw a rock upward with an initial velocity of 8.0 m/s. Determine the velocity and displacement of the rock at 4 s.
1
Expert's answer
2020-02-03T14:16:49-0500

v0=8.0  m/sv_0=8.0\; m/s

a=9.8  m/s2a=-9.8\; m/s^2

t=4  st=4\;s

v,Δy    ?v, \Delta y \;-\;?

Solution:


v=v0+atv=v_0+at

v=8.0+(9.8)×4=31.2  m/sv=8.0+(-9.8)\times4=-31.2 \; m/s


Δy=v0t+12at2\Delta y=v_0t+\frac{1}2at^2

Δy=8.0×4+12(9.8)×42=46.4  m\Delta y=8.0\times 4+\frac{1}{2}(-9.8)\times 4^2=-46.4 \;m


Answers: v=31.2  m/s,  Δy=46.4  m.v=-31.2\; m/s, \; \Delta y=-46.4\; m.



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