Answer to Question #102220 in Mechanics | Relativity for Nyx

Question #102220
A jet of water squirts out horizontally from a
hole on the side of the tank as shown below.
If the hole has a diameter of 3.75 mm , what
is the height of the water above the hole in
the tank?
Answer in units of cm.
1
Expert's answer
2020-02-07T10:24:03-0500


Assume that y = 1.23 m and x = 0.546 m.


t2=2yg=2(1.23)9.8t^2=\frac{2y}{g}=\frac{2(1.23)}{9.8}

t=0.501 st=0.501\ s

v=xt=0.5460.501=1.09msv=\frac{x}{t}=\frac{0.546}{0.501}=1.09\frac{m}{s}

We have:


0.5ρv2=ρgh0.5\rho v^2=\rho gh

h=v22g=1.0922(9.8)=0.0606 m=6.06 cmh=\frac{v^2}{2g}=\frac{1.09^2}{2(9.8)}=0.0606\ m =6.06\ cm


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Comments

WORKU TAGELE
05.09.21, 15:29

Thanks,continue it's important for students

Assignment Expert
18.02.20, 17:14

Dear visitor, please use panel for submitting new questions

carlos
18.02.20, 11:22

What's the use of providing the diameter of the hole. It's never used

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