Question

A jet of water squirts out horizontally from a

hole on the side of the tank as shown below.

If the hole has a diameter of 3.75 mm , what

is the height of the water above the hole in

the tank?

Answer in units of cm.

Answer 1

Assume that y = 1.23 m and x = 0.546 m.

$$t^2=\frac{2y}{g}=\frac{2(1.23)}{9.8}$$

$$t=0.501\ s$$

$$v=\frac{x}{t}=\frac{0.546}{0.501}=1.09\frac{m}{s}$$

We have:

$$0.5\rho v^2=\rho gh$$

$$h=\frac{v^2}{2g}=\frac{1.09^2}{2(9.8)}=0.0606\ m =6.06\ cm$$