Answer to Question #102220 in Mechanics | Relativity for Nyx

Question

A jet of water squirts out horizontally from a
hole on the side of the tank as shown below.
If the hole has a diameter of 3.75 mm , what
is the height of the water above the hole in
the tank?
Answer in units of cm.

Answer 1

Assume that y = 1.23 m and x = 0.546 m.

$t^2=\frac{2y}{g}=\frac{2(1.23)}{9.8}$

$t=0.501\ s$

$v=\frac{x}{t}=\frac{0.546}{0.501}=1.09\frac{m}{s}$

We have:

$0.5\rho v^2=\rho gh$

$h=\frac{v^2}{2g}=\frac{1.09^2}{2(9.8)}=0.0606\ m =6.06\ cm$