Question #100811
If the displacement of a body at an instant is given by:
X=22+At+B root t
Where(x)is measured in meters and (t)is measured in seconds.
Find dimensions of A and B
1
Expert's answer
2019-12-27T08:56:34-0500

The given equation is X=22+At+Bt1/2X=22+At+B {t}^{1/2}


It is given that |X|=m and |t|=s

where |X| notates the dimensions of the x term which is meters,and |t| notates the dimensions of the t term which is seconds.


For the addition of terms in an equation, each of the terms should posses the same dimensions.


 X=22=At=Bt1/2 X=AtA=m/s =ms1(1) X=Bt1/2B=m/s1/2B=ms1/2(2)\because\ |X|=|22|=|At|=|Bt^{1/2}| \\~\\ |X|=|A||t| \newline |A|=m/s\ =ms^{-1}\to(1)\\~\\ |X|=|B||t^{1/2}| \newline |B|=m/s^{1/2} \newline |B|=ms^{-1/2} \to(2)



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