According to young modulus equation
"E=FL\/A\\Delta"L
Where F is applied Force, L is length of the iron bar, A is cross sectional area of the iron bar and
"\\Delta L" is shorten length
therefore,
"\\Delta L=FL\/AE"
"\\Delta L=\\frac{2500*2}{0.006*1.83 * 10^{11}} \\newline"
"\\Delta L=4.5537\\mu m"
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