A point charge Q1 = 10C is at the origin, and a second charge Q2 = -5C is placed on the yaxis at y = 1m. What is the total electric field at the point P with coordinates x=2m, y=1m?
Answer
Electric field due to Q1
"E_1=\\frac{kQ1}{|r-r'|^3}(r-r') \n\\\\=\\frac{9\\times10^9\\times10}{(\\sqrt{5}^3)}(-2i-j) \\\\=4.02\\times10^{10}(-2i-j) N\/C"
"=-(8.04i+4.02j) \\times10^{10}N\/C"
Electric field due to Q2
"E_2=\\frac{kQ2}{|r-r'|^3}(r-r') \n\\\\=\\frac{9\\times10^9\\times10}{({2}^3)}(-2i) \\\\=2.28\\times10^{10}(-i) N\/C"
So total electric field at this point
"E=E_1+E_2\\\\=-(10.32i +4.02j)\\times10^{10}N\/C"
Comments
Leave a comment