Answer to Question #185213 in Field Theory for Esmail

Question #185213

A point charge Q1 = 10C is at the origin, and a second charge Q2 = -5C is placed on the y￾axis at y = 1m. What is the total electric field at the point P with coordinates x=2m, y=1m?


1
Expert's answer
2021-04-28T20:19:31-0400

Answer

Electric field due to Q1

E1=kQ1rr3(rr)=9×109×10(53)(2ij)=4.02×1010(2ij)N/CE_1=\frac{kQ1}{|r-r'|^3}(r-r') \\=\frac{9\times10^9\times10}{(\sqrt{5}^3)}(-2i-j) \\=4.02\times10^{10}(-2i-j) N/C

=(8.04i+4.02j)×1010N/C=-(8.04i+4.02j) \times10^{10}N/C

Electric field due to Q2

E2=kQ2rr3(rr)=9×109×10(23)(2i)=2.28×1010(i)N/CE_2=\frac{kQ2}{|r-r'|^3}(r-r') \\=\frac{9\times10^9\times10}{({2}^3)}(-2i) \\=2.28\times10^{10}(-i) N/C


So total electric field at this point

E=E1+E2=(10.32i+4.02j)×1010N/CE=E_1+E_2\\=-(10.32i +4.02j)\times10^{10}N/C



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