Question #185210

A charge of +3µC is distributed along a rod which on the x-axis extending from x=1m to

4m. a) What is the linear charge density of the rod? b) Find the electric field at the origin due to the charged rod.


Expert's answer

Answer

a. Linear charge density of rod

λ=Ql=3×10641=1μC/m\lambda=\frac{Q}{l}\\=\frac{3\times10^{-6}}{4-1}\\=1\mu C/m

b. Electric field is given at origin

E=2kλd(d+l)=2×9×109×1061×4=4500N/C.E=\frac{2k\lambda}{d(d+l)}\\=\frac{2\times9\times10^9\times10^{-6}}{1\times4}\\=4500N/C.





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