Answer to Question #182868 in Field Theory for Esmail

Question

A point charge of 4µC is 10cm distant from a second point charge of −2 µC. Calculate the magnitude of the force on each charge.

Answer 1

The force between two point charges can be calculated according to Coulomb's law

$F = k \frac{q_1 q_2}{r^2}$,

where $q_1, q_2$ are the charges, $r$ is the distance between them and $k = 9 \cdot 10^9 \frac{N \cdot m^2}{C^2}$is Coulomb's constant.

Hence, $F = 9 \cdot 10^9 \frac{N \cdot m^2}{C^2} \cdot \frac{4 \cdot 10^{-6} C \cdot 2 \cdot 10^{-6} C}{(0.1 m)^2} \approx 7.2 N$