Answer to Question #181026 in Field Theory for anthony

Question #181026

What is the electric field strength at a point in space 4 m due east of a particle with a charge of +8 μC? What

is the direction of the field here?



1
Expert's answer
2021-04-15T10:31:31-0400

Answer

Electric field at a point in space can be given as

E=kqr2E=\frac{kq}{r^2}


So

E=(9×109)(8×106)42E=4500N/CE=\frac{(9\times10^9) (8\times10^{-6}) }{4^2}\\E=4500N/C


Direction will be towards east.






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