1. A square metal plate with a length of 0.20 m and with a charge of 9.7 x 10 -7 C. Find the electric field of the square metal plate.
Answer
Electric field due to square plate
E=σ2ϵ0=q2Aϵ0=9.7×10−72×0.2×0.2×8.85×10−12=1.4×106N/CE=\frac{\sigma }{2\epsilon _0}\\=\frac{q}{2A\epsilon _0}\\=\frac{9.7\times10^{-7}}{2\times0.2\times0.2\times8.85 \times10^{-12} }\\=1.4\times10^{6}N/CE=2ϵ0σ=2Aϵ0q=2×0.2×0.2×8.85×10−129.7×10−7=1.4×106N/C
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