On a 200 km bike cycle ride, you ride the first 90 km at an average speed of 20m/s. What must your average speed over the next 40 km to be have your average speed for the total 200 km be?
a. 60m/s.
b. Given this average speed for the first 90 km, can you possibly attain an average speed of 80 m/s for the total 200 km ride? Explain.
Answer
a) time taken for 90km (t)
="\\frac{90000}{20}=45000" sec
Time taken for rest
(t') ="\\frac{20000-90000}{x}=110000\/x" sec
So average speed(given)
=total diatance/total time
"60=\\frac{20000}{4500+\\frac{110000}{x}}"
x="-\\frac{110000}{1.167}m\/s"
Speed is negative which is not possible.
b) now average speed 80m/s
"800=\\frac{20000}{4500+\\frac{110000}{x}}"
x=-55m/s
Speed is negative which is not possible.
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