Question #158730

Given three vectors A = 24i + 33j, B = 55i - 12j and C = 2i + 43j

 (a) Find the magnitude of each vector.

 (b) Write an expression for the vector difference A - C.

 (c) Find the magnitude and direction of the vector difference A-B.

 (d) In a vector diagram show vector A + B, and A - B, and also show that your diagram agrees 



Expert's answer

a)


A=242+332=41B=552+122=56C=22+432=43A=\sqrt{24^2+33^2}=41\\B=\sqrt{55^2+12^2}=56\\C=\sqrt{2^2+43^2}=43\\

b)


A−C=(24−2,33−43)=(22,−10)\bold{A-C}=(24-2,33-43)=(22,-10)

c)


A−B=(24−55,33−(−12))=(−31,45)\bold{A-B}=(24-55,33-(-12))=(-31,45)

∣A−B∣=312+452=55|A-B|=\sqrt{31^2+45^2}=55

θ=90−arctan⁡4531=125°\theta=90-\arctan{\frac{45}{31}}=125\degree

d)


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