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A rectangular metal waveguide filled with a dielectric of relative permittivity εr = 4, has the inside dimensions 3 x 1.2 cm, the cut off frequency for the dominant mode is
Answer
Vp=c(μrεr)hereμr=1;εr=4(given).Sofc=Vp2afc=3×108((3×10−2)(1×4)fc=2.5GHzV_p = \frac{c }{\sqrt{(μ_rε_r)} }\\here \\μ_r =1 ; ε_r = 4 (given). \\So \\f_c =\frac{V_p}{2a} \\f_c=\frac{3\times10^8}{((3\times10^{-2})\sqrt{(1\times4}) }\\f_c=2.5GHzVp=(μrεr)chereμr=1;εr=4(given).Sofc=2aVpfc=((3×10−2)(1×4)3×108fc=2.5GHz
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