Answer to Question #101529 in Field Theory for Christian Gray

Question

Point charge 2.5
μC
μC
is located at
x
x
= 0,
y
y
= 0.30
m
m
, point charge -2.5
μC
μC
is located at
x
x
= 0
y
y
= -0.30
m
m
. What are (a)the magnitude and (b)direction of the total electric force that these charges exert on a third point charge
Q
QQ
= 5.0
μC
μC
at
x
x
= 0.40
m
m
,
y
y
= 0?


Part A
Express your answer using two significant figures.




|F|
|F|
=

nothing
N
N

SubmitRequest Answer
Part B




θ
θ
=

nothing

∘
∘
clockwise from the
+x
+x
direction

Answer 1

the above picture represent the actual case of the above problem where F1 is the force exerted by the charge q1 and F2 is the force exerted by the q2 and F1 and F2 are equal in magnitude and F(resultant) is the net force of F1 and F2

force is given by formula $F=Kq_1q_2/r^2$

F1=F2= 9*10⁹*2.5*10^-6*5*10^-6/(0.5)²

F1=F2= 0.45 N

F(resultant)=2*0.45*cos$\theta$ = 2*0.45*3/5 = 0.54 N