Answer to Question #100440 in Field Theory for Derickson

Question

A cage is lowered down a pit shaft, 600m deep in 46 seconds. What is its average speed in meters per second and kilometers per hour?

Answer 1

$$v=\frac{600}{46}=13\frac{m}{s}$$

$$v=\frac{600}{46}3.6=47\frac{km}{h}$$