Answer to Question #100889 in Field Theory for balqis

Question #100889
consider a parallel plate capacitor with value of capacitance C =100(10^-6) F, the plate area,A =0.18m^2 and dielectric constant, εr=7.0
1
Expert's answer
2020-01-03T09:19:20-0500

A parallel plate capacitor with a dielectric between its plates has a capacitance given by C=kAϵ0dC=k \dfrac{A\epsilon_0}{d} , where κ is the dielectric constant of the material,AA is the area of the plate and dd is the distance between the two plates and ϵ0\epsilon_0 is called the permittivity of free space whose value is 8.8510128.85*10^{-12}

putting all the values in the above equation


    100106=70.188.851012/d\implies100*10^{-6}=7*0.18*8.85*10^{-12}/d

    d=0.11106m\implies d=0.11*10^{-6} m

    \implies d=0.11μmd=0.11{\mu}m



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