Electricity and Magnetism Answers

a charge of 20 x 10-6 c is 20 cm from another charge of 60 x 10-6 c. (b) determine the ep midway between them.

a charge of 20 x 10-6 c is 20 cm from another charge of 60 x 10-6 c. (b) determine the ep midway between them.

A charge of 20 x 10-6 C is 20 cm from another charge of 60 x 10-6 C. (a) Find the force between them. (b) Determine the Ep midway between them.

Two charges lie on positive x-axis. Charge A (2.0 x 10-9 C) is 4.0 cm from the origin and Charge B is 8.0 cm from the origin. (-3.0 x 10-9 C). What is the total force exerted by these two charges on Charge C (5.0 x 10-9 C) located at the origin?Solve for ForceBonC.

An electric field with a magnitude of 2.20 𝑘𝑁/𝐶 is applied along the x-axis. Calculate the

electric flux through a rectangular plane 0.77 m wide and 1.44 m long assuming that (a) the

plane is parallel to the yz plane; (b) the plane is parallel to the xy plane; (c) the plane

contains the y axis, and its normal makes an angle of 26.7° with the x axis.

An electric field with a magnitude of 2.20 𝑘𝑁/𝐶 is applied along the x-axis. Calculate the

electric flux through a rectangular plane 0.77 m wide and 1.44 m long assuming that (a) the

plane is parallel to the yz plane; (b) the plane is parallel to the xy plane; (c) the plane

contains the y axis, and its normal makes an angle of 26.7° with the x axis.

Calculate the work done by a force F vector = (x-y) i^ +xy j^

in moving a particle

counterclockwise along the circle x² +y² =4 from the point (2,0) to the point

(0, -2).

Determine the value of the constant a for which the vector field

F vector =(2x²y+ z²) i^ +(xy² -x²z) j^ +(axyz -2x²y²) k^

is solenoidal.

For very large resistances it is easy to construct R-C circuits that have time constants of several seconds or minutes. How might this fact be used to measure very large resistances, those that are too large to measure by more conventional means?

The direction of current in a battery can be reversed by connecting it to a second battery of greater emf with the positive terminals of the two batteries together. When the direction of current is reversed in a battery, does its emf also reverse? Why or why not?