A charge of 20 x 10-6 C is 20 cm from another charge of 60 x 10-6 C. (a) Find the force between them. (b) Determine the Ep midway between them.
a)
F=k(q12−q22)r2=720 N,F=\frac{k(q_1^2-q_2^2)}{r^2}=720~N,F=r2k(q12−q22)=720 N,
b)
E=4k(q1−q2)r2=36 MVm.E=\frac{4k(q_1-q_2)}{r^2}=36~\frac{MV}m.E=r24k(q1−q2)=36 mMV.
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