Answer to Question #99606 in Electricity and Magnetism for Ali hamza

Question #99606
Two singly ionized atoms move out of a slit at point S, as shown in figure, and into a magnetic
field of magnitude 0.100 T pointing into the page. Each has a speed of 1.00 × 106 m s−1
. The nucleus of the
first atom contains one proton and has a mass of 1.67 × 10−27 kg, whereas the nucleus of the second atom
contains a proton and a neutron and has a mass of 3.34 × 10−27 kg. Find their distance of separation when
they strike a photographic plate at P.
1
Expert's answer
2019-12-02T09:48:05-0500

According to Newton's second law, from the equilibrium between the centripetal force and the Lorentz force calculate the radii of the orbits:


qvB=mv2r, r=mvqB.qvB=m\frac{v^2}{r},\\ \space\\ r=\frac{mv}{qB}.

For the first and the second atom it gives respectively


r1=0.104 m,r2=0.208 m.r_1=0.104 \text{ m},\\ r_2=0.208\text{ m}.

For the situation shown in the figure the separation will be


d=2(r2r1)=0.208 m.d=2(r_2-r_1)=0.208\text{ m}.

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Comments

Deus Ziyaka
30.04.23, 05:55

Simple and straight forward calculation

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