We depict the equivalent equivalent circuit
We write Ohm's law
I=URI=\frac{U}{R}I=RU
Where do we write
R=UI=120(V)12(A)=10(Om)R=\frac{U}{I}=\frac{120(V)}{12(A)}=10(Om)R=IU=12(A)120(V)=10(Om)
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