Answer to Question #98905 in Electricity and Magnetism for Gyana

Question

A conductor of length 5cm is moved parallel to itself with a speed of 2m/s , perpendicular to a uniform magnetic field of 1/10³ Wb/m³. The induced emf is??

Answer 1

emf is given by formula

$E=Blv /sin{θ} (1)$

In our case, we have B=1/10³ Wb/m³, l=0.05 m, v=2m/s

Using (1) we got

E=100 V

Answer

100 V