I should correct the answer d):
d) if one charge is removed, an uncompensated tension arises, which is opposite in the direction to the field strength of the removed charge, that is, the resulting force is equal "f = \\frac{kqQ}{R^2}" , where R is the radius of the circumscribed circle. The result can be obtained by direct calculation: force "F = \\frac{2kqQ}{R^2}(cos\\alpha + cos2\\alpha + ... + cos6\\alpha) = \\frac{kqQ}{R^2}" , where the angle "\\alpha = \\frac{360}{13}."
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