Answer to Question #97039 in Electricity and Magnetism for Nikolai

Question

When the current in the wire is 0.20 A, the magnetic field strength at the upper section of wire due to the lower section of wire is 1.3 x 10^-4 T.

Calculate the magnetic force acting per unit length on the upper section of wire.

Answer 1

$$\frac{F}{l}=BI=(1.3\cdot 10^{-4})(0.2)=2.6\cdot 10^{-5}\frac{N}{m}$$