Electric force between two charged object are:
F=r2kQ1Q2
Now, we need to find out the charge of the iron samples:
Each bar has a mass of 1 kg.
So, the number of atoms in each bar is: Na=m/n=6∗1026/58=1.0344∗1025atoms
Each atom has 26 protons: Np=26Na=2.69∗1026protons
The exceeding charge of the each rod is: Q=0.01Na∗qe=4.304∗105C
Finally, the force between two rods:
F=r2kQ1Q2=129∗109∗4.3042∗1010=1.46∗1021N
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