Answer to Question #92159 in Electricity and Magnetism for Neha

Question #92159
Suppose the exact charge neutrality does not hold in a world and the electron has a charge 1%less in magnitude than the proton. Calculate the coulomb force acting between two blocks of iron each of mass 1kg separated by a distance of 1m. Number of protons in an iron atom=26 and 58kg of iron contains 6*10^26 atoms.
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Expert's answer
2019-07-30T09:14:50-0400

Electric force between two charged object are:


F=kQ1Q2r2F=\frac{kQ_1Q_2}{r^2}


Now, we need to find out the charge of the iron samples:

Each bar has a mass of 1 kg.

So, the number of atoms in each bar is: Na=m/n=61026/58=1.03441025atomsN_a=m/n=6*10^{26}/58=1.0344*10^{25} atoms

Each atom has 26 protons: Np=26Na=2.691026protonsN_p=26N_a=2.69*10^{26} protons


The exceeding charge of the each rod is: Q=0.01Naqe=4.304105CQ=0.01N_a*q_e=4.304*10^5 C


Finally, the force between two rods:


F=kQ1Q2r2=91094.3042101012=1.461021NF=\frac{kQ_1Q_2}{r^2}=\frac{9*10^9 *4.304^2*10^{10}}{1^2}=1.46*10^{21}N


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