Question:
A rectangular loop of wire that can rotate about an axis through its center is placed between the poles of a magnet in a magnetic field with a strength of 0.357 T (with the magnetic field parallel to the plane of the loop). The length of the loop L is 15.5 cm and its width w is 10.0 cm. What emf is developed in the loop if the loop is rotated form this position, in 1.00 ms, to a position where the plane of the loop makes an angle of 54.5 degrees with the magnetic field.
Solution:
According to the Faraday law emf E = dФ/dt ≈ ΔФ/Δt = LwBcos(90-54.5)/Δt = 1.55*3.57*cos35.5 = 4.5 (V).
The answer:
The emf E = 4.5 V.
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