Answer to Question #287198 in Electricity and Magnetism for Angel

Question #287198

A soccer goal, found in a city park, is made of tubing that supports an


odd-shade hanging net behind the goal, but has a rectangular opening


in front. The height of the opening is 2.8m and the width is 3.5m.


If a uniform electric field, with magnitude of 0.1N/C, passes through


the goal from the front to the back, entering at 90 degrees to the plane


of the goal opening, what is the flux through the net? Also, find the flux


through the net if the electric field enters the goal at 60 degrees angle


to the plane of the front of the goal. In both cases, assume that there is


no charge found inside the goal itself.

1
Expert's answer
2022-01-13T09:20:11-0500

The flux at 90° is


"\\Phi=EA=Eab=0.98\\text{ N}\u00b7\\text m^2\/\\text C."

At 60°:


"\\Phi=EA\\sin60\u00b0=Eab\\sin60\u00b0=0.85\\text{ N}\u00b7\\text m^2\/\\text C."


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