i) Electric field"|\\overrightarrow{E}|=\\frac{\\Delta V}{d}"
"|\\overrightarrow{E}|=\\frac{50}{10\\times 10^{-3}}V\/m"
"\\Rightarrow |\\overrightarrow{E}|=5\\times10^{-3}V\/m"
ii) Potential of sample with respect to ground is 50V because grid is grounded.
Comments
Leave a comment