Single point-like charge produce electric field E:
"\\displaystyle E = \\frac{1}{4 \\pi \\epsilon_0} \\frac{q}{r^2}"
"\\displaystyle \\frac{1}{4 \\pi \\epsilon_0} = 8,987 \\cdot 10^9 \\; [\\frac{N \\cdot m^2}{C^2}], r=2\\, m."
So, depending on the value of charge, E will be
"\\displaystyle E= \\frac{8.987 \\cdot 10^9}{4} q =2.247 q \\;[\\frac{V}{m}]"
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