Question #145433
an isolated charged point partivle produces elwctric foreld E at 2m away claculate E at 2m away?
1
Expert's answer
2020-11-20T09:35:12-0500

Single point-like charge produce electric field E:

E=14πϵ0qr2\displaystyle E = \frac{1}{4 \pi \epsilon_0} \frac{q}{r^2}

14πϵ0=8,987109  [Nm2C2],r=2m.\displaystyle \frac{1}{4 \pi \epsilon_0} = 8,987 \cdot 10^9 \; [\frac{N \cdot m^2}{C^2}], r=2\, m.

So, depending on the value of charge, E will be

E=8.9871094q=2.247q  [Vm]\displaystyle E= \frac{8.987 \cdot 10^9}{4} q =2.247 q \;[\frac{V}{m}]


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