Single point-like charge produce electric field E:
E=14πϵ0qr2\displaystyle E = \frac{1}{4 \pi \epsilon_0} \frac{q}{r^2}E=4πϵ01r2q
14πϵ0=8,987⋅109 [N⋅m2C2],r=2 m.\displaystyle \frac{1}{4 \pi \epsilon_0} = 8,987 \cdot 10^9 \; [\frac{N \cdot m^2}{C^2}], r=2\, m.4πϵ01=8,987⋅109[C2N⋅m2],r=2m.
So, depending on the value of charge, E will be
E=8.987⋅1094q=2.247q [Vm]\displaystyle E= \frac{8.987 \cdot 10^9}{4} q =2.247 q \;[\frac{V}{m}]E=48.987⋅109q=2.247q[mV]
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