As point P is very far from the dipole, given dipole can be considered as a point dipole.
From Coulumb’s Law for a point dipole electric field on axial line is
"E_a = \\frac{2kp}{R^3}"
p = qd
Electric field on equatorial line is
"E_e = -\\frac{kp}{R^3}"
"E_2 = \\frac{2kpcos\u03b8}{R^3}"
"E_1 = -\\frac{kpsin\u03b8}{R^3}"
The net field at P is
"E = \\sqrt{E_1^2 + E_2^2} = \\frac{kp}{R^3}\\sqrt{sin^2\u03b8 + 4cos^2\u03b8} = \\frac{kp}{R^3}\\sqrt{1 + 3cos^2\u03b8}"
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